Josh Allen and Lamar Jackson are favorites in this year's NFL MVP race. Now, on Sunday, they'll face off for a lot more than an individual accolade as the Buffalo Bills play host to the Baltimore Ravens in a fight to reach the AFC championship.

Lamar Jackson and Josh Allen. The two star quarterbacks have electrified fans, each having MVP-caliber seasons, and will meet in the AFC divisional round to settle things. Jackson and Allen are both known for their ability to make plays with their legs.

ORCHARD PARK, NEW YORK – JANUARY 12: Josh Allen #17 of the Buffalo Bills throws a pass against the Denver Broncos in the fourth quarter during the AFC Wild Card Playoffs at Highmark Stadium on January 12, 2025 in Orchard Park, New York. (Photo by Timothy T Ludwig/Getty Images)

Lamar Jackson vs. Josh Allen highlights NFL playoff slate: Who deserves MVP? This weekend's divisional round of the NFL playoffs features two quarterbacks in remarkably similar positions. Josh Allen of the Buffalo Bills and Lamar Jackson of the Baltimore Ravens are the leading MVP candidates this season.

The hardy souls across western New York and inside Highmark Stadium never ask for much, just that elusive first Super Bowl championship, but first Josh Allen with the ball in his hands last on Sunday night.

Baltimore and Buffalo's Divisional Round matchup positions the superstar quarterbacks for an all-time showdown.

Lamar Jackson, Josh Allen are both downplaying the AP NFL MVP storyline ahead of divisional round matchup between Ravens and Bills

Sometimes you get one like we get in Buffalo on Sunday night when it is Josh Allen and the Bills going against Lamar Jackson and the Ravens.

Liz Loza and Daniel Dopp break down the NFL divisional round and offer their favorite prop bets for the games.

Two of the top mobile quarterbacks in the league go head-to-head during the Bills-Ravens divisional-round game.

Throughout the sports card hobby, Josh Allen is regarded as one of the most sought after players and acquiring his cards can be a game-changer for any collection.